If cot B = $\frac{12}{5}$, what is the value of sec B ?
Answer & explanation
Correct answer: option 2
cotB = \(\frac{12}{5}\)
Using pythagoras theorem ,
P2 + B2 = H2
52 + 122 = H2
H2 = 169
H = 13
Now , secB = \(\frac{13}{12}\)
If cot B = $\frac{12}{5}$, what is the value of sec B ?
Correct answer: option 2
cotB = \(\frac{12}{5}\)
Using pythagoras theorem ,
P2 + B2 = H2
52 + 122 = H2
H2 = 169
H = 13
Now , secB = \(\frac{13}{12}\)