A charge q moves with a velocity of $2 ms^{-1}$ along x-axis in a uniform magnetic field $\vec{B}=\hat{i}+2 \hat{j}+3 \hat{k}$, then charge will experience a force.

In z-y plane

The correct answer is Option (1) → In z-y plane

According to Lorentz force,

$\vec F=q(\vec v×\vec B)$

$=q((2\hat i)×(\hat i-2\hat j+3\hat k))$

$=q(-6\hat j+4\hat k)$

Hence, charge will experience force in z-y direction.