Practicing Success
A set contains n elements. The power set contains |
n elements 2n elements n2 elements none of these |
2n elements |
Set contains n elements power set contains subsets having 0, 1, 2, 3,..., n elements so number of elements in Power set $={^nC}_0+{^nC}_1+{^nC}_2+....+{^nC}_n=(1+1)^n=2^n$ |