The ratio of the sides of a triangle is 11 : 11 : 4. If the area is 2$\sqrt{117}$ cm², then what is the length of the equal sides?

11 cm

Area of a triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

where, s = semi-perimeter

a, b, c is the sides

Let the sides of the triangle = $11x, 11x, 14x$

s = $\frac{11x+11x+4x}{2}$

  = 13x

Area =  $\sqrt{13x(13x-11x)(13x-11x)(13x-4x)}$

        = $\sqrt{13x \times 2x \times 2x \times 9x}$

        = 2x²$\sqrt{117}$

Given that area  = 2$\sqrt{117}$ cm²

x = 1,

Thus, the sides of the triangle = 11cm, 11cm, 4cm