The moment of inertia of a uniform circular disc of radius 'R' and mass 'M' about an axis passing from the edge of the disc and normal to the disc is :
Answer & explanation
Correct answer: option 3
\(I = I_{CM} + Md^2\)
\(I_{CM} = \frac{MR^2}{2} \text{ ; } d = R \)
\(I = \frac{3}{2}MR^2\)