Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

The moment of inertia of a uniform circular disc of radius 'R' and mass 'M' about an axis passing from the edge of the disc and normal to the disc is :

Options:

\(\frac{1}{2}MR^2\)

\(\frac{7}{2}MR^2\)

\(\frac{3}{2}MR^2\)

\(MR^2\)

Correct Answer:

\(\frac{3}{2}MR^2\)

Explanation:

\(I = I_{CM} + Md^2\)

\(I_{CM} = \frac{MR^2}{2} \text{ ; } d = R \)

\(I = \frac{3}{2}MR^2\)