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A circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 8.4 cm, BC = 9.8 cm and CD = 5.6 cm. The length of side AD, in cm, is: |
4.9 4.2 3.8 2.8 |
4.2 |
Adding all these, we get (AP + BP) + (CR + DR) = (BQ + QC) + (DS + AS) AB + CD = BC + DA 8.4 + 5.6 = 9.8 + DA = DA = 14 - 9.8 = 4.2 cm Therefore, AD is 4.2 cm. |
