A circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 8.4 cm, BC = 9.8 cm and CD = 5.6 cm. The length of side AD, in cm, is:
Answer & explanation
Correct answer: option 2
Adding all these, we get
(AP + BP) + (CR + DR) = (BQ + QC) + (DS + AS)
AB + CD = BC + DA
8.4 + 5.6 = 9.8 + DA
= DA = 14 - 9.8 = 4.2 cm
Therefore, AD is 4.2 cm.