Match List-I with List-II
Choose the correct answer from the options given below : | ||||||||||||||||||||
(A)-(III),(B)-(IV), (C)-(I), (D)-(II) (A)-(IV),(B)-(I), (C)-(III), (D)-(II) (A)-(II),(B)-(III), (C)-(IV), (D)-(I) (A)-(II),(B)-(IV), (C)-(III), (D)-(I) |
(A)-(II),(B)-(III), (C)-(IV), (D)-(I) |
The correct answer is option (3) → (A)-(II),(B)-(III), (C)-(IV), (D)-(I) (A) → $\frac{1}{2}|\vec{a}×\vec{b}|$ (II) (B) → $|\vec{a}×\vec{b}|$ (III) (C) $(\vec{a}-\vec{b})×(\vec{a}+\vec{b})$ $=\vec a ×\vec a+\vec a×\vec b-\vec b×\vec a-\vec b×\vec b$ $=\vec a×\vec b+\vec a×\vec b=2(\vec a×\vec b)$ (IV) (D) $|\vec{a}||\vec{b}|\sin \theta \hat{n}=\vec a×\vec b$ (I) |