Practicing Success
Practicing Success
CUET Preparation Today
If x + \(\frac{1}{x}\) = 3, find \(\frac{x^3+\frac{1}{x}}{x^2+1-x}\). |
\(\frac{3}{2}\) \(\frac{7}{2}\) \(\frac{5}{2}\) \(\frac{11}{2}\) |
\(\frac{7}{2}\) |
\(\frac{x^3+\frac{1}{x}}{x^2+1-x}\) Divide by x. \(\frac{x^2+\frac{1}{x^2}}{x+\frac{1}{x}-1}\) = \(\frac{(3)^2-2}{3-1}\)=\(\frac{7}{2}\) |
