Practicing Success
If $sin\theta = √3cos \theta $, then what is the value of $\frac{3sin^2\theta +cos\theta}{2cos\theta +5}$ ? |
19/25 18/5 11/24 3/2 |
11/24 |
$sin\theta = √3cos \theta $ $\frac{sin\theta}{cos\theta}$ = $\sqrt{3}$ $tan\theta = \sqrt{3}$ ⇒ $\theta = 60°$ Thus, $\frac{3sin^2\theta +cos\theta}{2cos\theta +5}$ = $\frac{3sin^260° +cos60°}{2cos60° +5}$ = $\frac{3.\frac{3}{4} + \frac{1}{2}}{2.\frac{1}{2} + 5}$ = $\frac{11}{24}$
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