The area bounded by the parabola \(y^2=4ax\) and \(x^2=4ay\) is1\(\frac{8}{3}a^2\)2\(\frac{16}{3}a^2\)3\(\frac{32}{3}a^2\)4\(\frac{64}{3}a^2\)Answer & explanation+Correct answer: option 2Use integration
