The area bounded by the parabola \(y^2=4ax\) and \(x^2=4ay\) is

\(\frac{8}{3}a^2\) \(\frac{16}{3}a^2\) \(\frac{32}{3}a^2\) \(\frac{64}{3}a^2\)

\(\frac{16}{3}a^2\)

Use integration