Target Exam

CUET

Subject

General Aptitude Test

Chapter

Numerical Ability

Topic

Mean, Median and Mode

Question:

The marks out of 50 obtained by 100 students in a test are given below as:

Marks obtained

  20  

  25  

  28  

  29  

  33  

  38  

  42  

  43  

Number of students

6

20

24

28

15

4

2

1

Find the value of the (3 mode - 2 median).

Options:

27.5

31

30

28.8

Correct Answer:

30

Explanation:

The correct answer is Option (3) → 30

Let’s solve step by step.

Step 1: Organize the data

Marks (x)

Frequency (f)

Cumulative frequency (CF)

20

6

6

25

20

26

28

24

50

29

28

78

33

15

93

38

4

97

42

2

99

43

1

100

  • Total students = 100

Step 2: Find the Median

  • Median position = $\frac{N}{2} = \frac{100}{2} = 50^\text{th}$ value

The 50th value falls in the class 28–29 (cumulative frequency just reaching 50 at 28).

  • Median ≈ 28.5 (since 28 and 29 are close and majority of students around this group)

Step 3: Find the Mode

  • Mode = the value with the highest frequency
  • Highest frequency = 28 → Marks = 29

So, Mode = 29

Step 4: Calculate (3 × Mode − 2 × Median)

$3 \times 29 - 2 \times 28.5 = 87 - 57 = 30$