If sinx, cosx and tanx are in G.P.
then find the value of cot6x - cot2x = ?
Answer & explanation
Correct answer: option 3
If a,b,c are in G.P.
than b2 = ac
cos2x = sinx × tanx
cos2x = \(\frac{sinx\;×\;sinx}{cosx}\)
⇒ cos3x = sin2x
Divide by sin3x
we get,
cot3x = cosecx
Put in find
cosec2x-cot2x = 1