Practicing Success
If sinx, cosx and tanx are in G.P. then find the value of cot6x - cot2x = ? |
-1 0 1 4 |
1 |
If a,b,c are in G.P. than b2 = ac cos2x = sinx × tanx cos2x = \(\frac{sinx\;×\;sinx}{cosx}\) ⇒ cos3x = sin2x Divide by sin3x we get, cot3x = cosecx Put in find cosec2x-cot2x = 1 |