Two finite sets have m and n elements. The total number of subsets of the first set is 56 more than the total number of subsets of second set. The values of m and n are
Answer & explanation
Correct answer: option 2
$2^m–2^n= 56⇒2^n(2^{m-n}-1)=2^3×7$
by comparison $n=3$
$2^{m-3}-1=7⇒2^{m-3}=8$
$⇒m-3=3⇒m=6$
m = 6 and n = 3