Find the value of $\sin^{-1} \left[ \sin \left( -\frac{17\pi}{8} \right) \right]$. |
$\frac{\pi}{8}$ $-\frac{\pi}{8}$ $-\frac{17\pi}{8}$ $\frac{7\pi}{8}$ |
$-\frac{\pi}{8}$ |
The correct answer is Option (2) → $-\frac{\pi}{8}$ ## $\sin^{-1} \left[ \sin \left( -\frac{17\pi}{8} \right) \right] = -\sin^{-1} \left[ \sin \left( 2\pi + \frac{\pi}{8} \right) \right]$ $= -\frac{\pi}{8}$ |