Find the value of $\sin^{-1} \left[ \sin \left( -\frac{17\pi}{8} \right) \right]$.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $-\frac{\pi}{8}$ ##
$\sin^{-1} \left[ \sin \left( -\frac{17\pi}{8} \right) \right] = -\sin^{-1} \left[ \sin \left( 2\pi + \frac{\pi}{8} \right) \right]$
$= -\frac{\pi}{8}$