Practicing Success
Practicing Success
CUET Preparation Today
The magnitude of the vector \(\vec{a}\) = \(\hat{i}\) +2\(\hat{j}\)+3\(\hat{k}\)
|
√13 √14 √18 √16 |
√14 |
We have \(\vec{a}\) = \(\hat{i}\) +2\(\hat{j}\)+3\(\hat{k}\) |\(\vec{a}\)| = √(1)2 + (2)2+ (3)2 |\(\vec{a}\)| = √1+4+9 |\(\vec{a}\)| = √14 |
