A capacitor charged from a 100 V d.c supply is found to have charge of 20 µC. How much energy is stored in it?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $1 \times 10^{-3}J$
Energy stored in capacitor is -
$E=\frac{1}{2}QV$
$=\frac{1}{2}×20×10^{-6}×100$
$=1×10^{-3}J$