Practicing Success
a b c d |
d |
$ V = V_0 (1 - e^\frac{-t}{RC}) = \frac{V_0}{2}$ $\Rightarrow \frac{t}{RC} = ln2$ $\Rightarrow t = RC ln2$ $\text{For parallel arrangement } C_{eq} = 2C$ $\Rightarrow t_p= 2RC ln2$ $\text{For Series arrangemant } C_s = \frac{c}{2}$ $\Rightarrow t_s = \frac{RC}{2} ln2$ $\frac{t_s}{t_p} = \frac{1}{4}$ $\Rightarrow t_s = \frac{10}{4} = 2.5 Sec$ |