A ladder leaning against a wall makes an angle of 60° with the ground. If the length of the ladder is 19 m, then what is the distance of the foot of the ladder from the wall?

9.5 m

In a right angle triangle ,

cos A = \(\frac{B}{H}\) = \(\frac{AB}{AC}\)

According to question , A = 60º

So, cos 60º = \(\frac{AB}{19}\)

Now,

\(\frac{1}{2}\) = \(\frac{AB}{19}\) 

AB = 9.5m