Find the effective impedance in the circuit if the source is a) DC source and b) High frequency AC source.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → For DC, \( Z = R_1 \) and for AC, \( Z = R_2 + R_3 \)
An inductor has reactance \( \omega L \) and a capacitor has reactance \( \frac{1}{\omega C} \). At d.c. (\( \omega = 0 \)) an inductor is a plain wire and a capacitor is an open gap. At a very high frequency the inductor is practically an open gap and the capacitor is a plain wire.
(a) DC source
The inductors \( L_1 \), \( L_2 \) act as wires and the capacitors \( C_1 \), \( C_2 \) block the current. The upper branch carries the current through \( R_1 \) alone; the branch with \( C_2 \) is open.
\( Z = R_1 \)
(b) High frequency AC source
The inductors \( L_1 \), \( L_2 \) block the current, so the upper branch carries none, while the capacitors \( C_1 \), \( C_2 \) act as wires. The current goes through the lower branch, \( C_2 \), \( R_2 \) and \( R_3 \), with \( C_2 \) shorted.
\( Z = R_2 + R_3 \)