Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) |
(A)-(II), (B)-(I), (C)-(IV), (D)-(III) |
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
(A) Third order - (II) Reaction: Rate law: Total order = 2 + 1 = 3 (third order). (B) First Order - (I) Reaction: Hydrogenation reactions on catalyst surfaces often depend on only one reactant concentration, so the rate behaves as first order. (C) One and half order - (IV) Reaction: Rate law: Total order = 1 + 1/2 = 3/2 (one and half order). (D) Pseudo first order - (III) Reaction: Hydrolysis occurs in large excess of water, so [H₂O] remains almost constant. Thus the reaction behaves as pseudo first order.
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