A party of 23 persons take their seats at a round table. The odds against two persons sitting together are
Answer & explanation
Correct answer: option 1
$P=\frac{(21)!2!}{(22)!}=\frac{1}{11}=\frac{1}{1+10}$ ∴ odd against = 10 : 1
A party of 23 persons take their seats at a round table. The odds against two persons sitting together are
Correct answer: option 1
$P=\frac{(21)!2!}{(22)!}=\frac{1}{11}=\frac{1}{1+10}$ ∴ odd against = 10 : 1