The curve x = 4 - 3y - y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is : (in sq. units)
Answer & explanation
Correct answer: option 4
Area = \(\int_{-4}^{1}d\)y x
= \(\int_{-4}^{1}d\)y (4 - 3y - y2)
= 20\(\frac{5}{6}\)