An object is placed at 10 cm distance in front of concave mirror of radius of curvature 15 cm. Find the position of the image.

60 cm 1 m 30 cm 10 cm

30 cm

u = -10cm , f = -7.5cm $\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{-1}{7.5} + \frac{1}{10} = \frac{-1}{30}$ $ \Rightarrow v = -30cm$