How many times digit 3 appear in the counting from 1 to 1000?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 300
Write every number from 1 to 999 with three digits (7 as 007, 45 as 045); 1000 has no 3, and the added zeros do not change the count. The numbers 000 to 999 are all 1000 possible three-digit strings, so in each place every digit 0-9 appears equally often: 100 times.
3 in the units place: 3, 13, 23, …, 993, that is 100 times
3 in the tens place: 30-39 in each of the 10 hundreds, that is \(10\times10=100\) times
3 in the hundreds place: 300-399, that is 100 times
Total \(=100+100+100=300\)