The number of skew symmetric matrices of order 3 can be formed by using all elements of set {0, -a, a, -b, b, -c, c}
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 48
$A=\begin{pmatrix}0&a&b\\-a&0&c\\-b&-c&0\end{pmatrix}$
Number of skew-symmetric matrices = $3!×8$
$=6×8=48$