A man travels from Delhi to Chandigarh. If he travels 25% faster than his speed, he would reach at Chandigarh 15 minutes early. By how many minutes would he be late if he traveks 40% slower than usual speed?
Answer & explanation
Correct answer: option 3
Let usual speed = 100
25% faster = 125
Speed → 100 : 125
4 : 5
Time → 5 : 4 ..... (Diff. 1)
Difference = 1R = 15 min
actual time = 5R = 5× 15 = 75 min
⇒ Reduced speed by 40%
Usual speed = 100
New speed = 60
Speed → 100 : 60
5 : 3
Time → 3 : 5
Usual time = 75 min
3R → 75
1R → 25
5R → 125
Late by 125 - 75 = 50 mins