The equations: $x + 4y - 3 = 0$ and $2x + 8y - 6=0$ have

infinite solutions

The correct answer is Option (4) → infinite solutions

Let’s examine the two equations:

1. $x + 4y - 3 = 0$
2. $2x + 8y - 6 = 0$

Notice that the second equation is exactly twice the first:

$2(x + 4y - 3) = 2x + 8y – 6$

So, both equations represent the same straight line.

Therefore, the system has infinitely many solutions.