Practicing Success
Two equal sums(in ₹) are lent at 8% and 4% simple interest p.a, respectively at the same time.The first sum is received 2 years earlier than the other and the amount received in each case is ₹14,500. Each sum is: |
₹12,800 ₹12,500 ₹13,200 ₹12,000 |
₹12,500 |
By using formula , Amount = Principal + simple interest = Principal + \(\frac{Principal ×Rate × Time }{100}\) Amount received in both cases are equal . So , P + \(\frac{P ×8 × T }{100}\) = P + \(\frac{P ×4× (T +2)}{100}\) \(\frac{P ×8 × T }{100}\) = \(\frac{P ×4× (T +2)}{100}\) 8T = 4T + 8 4T = 8 T = 2 years To find out the initial sum , 14500 = P + \(\frac{P ×8 × T }{100}\) 14500 = P + \(\frac{P ×8 × 2 }{100}\) P = 14500 × \(\frac{100 }{116}\) = 12500 |