If A(2, 3), B(0, 6) and C(-5, 0) are the vertices of ΔABC, then find the coordinates of its centroid.

$(-1, 3)$

Centroid of triangle with vertices (a1,b1) , (a2,b2) & (a3,b3) are

( \(\frac{a1 + a2 + a3}{3}\) ,  \(\frac{b1 + b2 + b3}{3}\) )

So,

A = \(\frac{2 + 0 - 5}{3}\) 

= \(\frac{-3}{3}\)

= - 1

B = \(\frac{3 + 6 + 0}{3}\)

= \(\frac{9 }{3}\)

= 3

The correct answer is option (4) : $(-1, 3)$