If A(2, 3), B(0, 6) and C(-5, 0) are the vertices of ΔABC, then find the coordinates of its centroid.
Answer & explanation
Correct answer: option 4
Centroid of triangle with vertices (a1,b1) , (a2,b2) & (a3,b3) are
( \(\frac{a1 + a2 + a3}{3}\) , \(\frac{b1 + b2 + b3}{3}\) )
So,
A = \(\frac{2 + 0 - 5}{3}\)
= \(\frac{-3}{3}\)
= - 1
B = \(\frac{3 + 6 + 0}{3}\)
= \(\frac{9 }{3}\)
= 3
The correct answer is option (4) : $(-1, 3)$