Match List I with List II
| List I | List II |
| A. \([Co(NH_3)_5(NCS)](SO_3)\) | I. +4 |
| B. \([Co(NH_3)_4Cl_2]SO_4\) | II. 0 |
| C. \(Na_4[Co(S_2O_3)_3]\) | III. +2 |
| D. \([CO_2(CO)_8]\) | IV. +3 |
Choose the correct answer from the option given below:
Answer & explanation
Correct answer: option 3
The correct answer is 3. A-IV, B-I, C-III, D-II.
| List I | List II |
| A. \([Co(NH_3)_5(NCS)](SO_3)\) | IV. +3 |
| B. \([Co(NH_3)_4Cl_2]SO_4\) | I. +4 |
| C. \(Na_4[Co(S_2O_3)_3]\) | III. +2 |
| D. \([CO_2(CO)_8]\) | II. 0 |
Let us calculate the oxidation number of the central metal atom/ion in each of the given complexes:
A. \([Co(NH_3)_5(NCS)](SO_3)\):
Let the oxidation number of \(Co\) be \(x\)
We know,
Charge of \(NH_3\) ligand is \(0\)
Charge of \(NCS\) ligand is \(-1\)
Charge of \(SO_3\) ligand is \(-2\)
The overall charge of the complex should be \(0\)
Thus,
\(x + 5(0) + (-1) + (-2) = 0\)
or, \(x + 0 -1 -2 = 0\)
or, \(x - 3 = 0\)
or, \(x = 3\)
Hence, the oxidation number of \(Co\) ion is \(+3\).
B. \([Co(NH_3)_4Cl_2]SO_4\):
Let the oxidation number of \(Co\) be \(x\)
We know,
Charge of \(NH_3\) ligand is \(0\)
Charge of \(Cl\) ligand is \(-1\)
Charge of \(SO_4\) ligand is \(-2\)
The overall charge of the complex should be \(0\)
Thus,
\(x + 4(0) + 2(-1) + (-2) = 0\)
or, \(x + 0 -2 -2 = 0\)
or, \(x - 4 = 0\)
or, \(x = 4\)
Hence, the oxidation number of \(Co\) ion is \(+4\).
C. \(Na_4[Co(S_2O_3)_3]\):
Let the oxidation number of \(Co\) be \(x\)
We know,
Charge of \(Na\) is \(+1\)
Charge of \(S_2O_3\) ligand is \(-2\)
The overall charge of the complex should be \(0\)
Thus,
\( 4(1) + x + 3(-2) = 0\)
or, \(4 + x + -6 = 0\)
or, \(x - 2 = 0\)
or, \(x = 2\)
Hence, the oxidation number of \(Co\) ion is \(+2\).
D. \([CO_2(CO)_8]\):
Let the oxidation number of \(Co\) be \(x\)
We know,
Charge of \(CO\) is \(0\)
Thus,
\(2x + 8(0) = 0\)
or, \(x = 0\)
Hence, the oxidation number of \(Co\) is \(0\).
So from these calculations it is clear that the correct answer is option 3. A-IV, B-I, C-III, D-II.