Practicing Success
Practicing Success
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(mx + n ) is a factor of : |
$ m^2x^2 +2nx +n^2$ $ m^2x^2 +2mnx +n^2$ $ m^2x^2 +2mx +n^2$ $ m^2x^2 +2mn +n^2$ |
$ m^2x^2 +2mnx +n^2$ |
(mx + n) = (mx + n)2 = m2x2 + 2mnx + n2 So, (mx + n) is a factor of m2x2 + 2mnx + n2 |
