Practicing Success
Practicing Success
CUET Preparation Today
If f(x) = 3x – 5, then$ f^{ -1} (x)$ is : |
if given by $\frac{1}{3 x-5}$ is given by $\frac{x+5}{3}$ does not exist because f is not one – one does not exist because f is not onto. |
is given by $\frac{x+5}{3}$ |
Let y=f(x)=3x−5 Clearly f(x) is one-one onto function so it is invertible.
⇒y=3x−5
$\Rightarrow x = \frac{y+5}{3}$
$\Rightarrow f^{-1}(x) = \frac{x+5}{3}$
(2) is the correct answer. |
