Which of the following statements, for the reaction of type A → B, are correct?
(A) The initial rates for a second order reaction depend on the square of the concentration of the reactant
(B) The half-life is the time for half of the reactant to be consumed
(C) The expression for rate of second order reaction is \( r = k[2A]^2 \)
(D) The half-life of a second-order reaction depends on the initial concentration
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A), (B) and (D) only
For a reaction of the type A → B that is second order, the rate is proportional to the square of the concentration of A, and the rate constant has the unit L mol−1 s−1:
\( \displaystyle r = k[\mathrm{A}]^{2} \)
Integrating this rate law gives the half-life:
\( \displaystyle \frac{1}{[\mathrm{A}]} - \frac{1}{[\mathrm{A}]_0} = kt \Rightarrow t_{1/2} = \frac{1}{k[\mathrm{A}]_0} \)
(A) The initial rates for a second order reaction depend on the square of the concentration of the reactant — Correct. With \( r = k[\mathrm{A}]^2 \), doubling the initial concentration makes the initial rate four times.
(B) The half-life is the time for half of the reactant to be consumed — Correct. This is the definition of half-life: the time in which the concentration falls to half its initial value.
(C) The expression for rate of second order reaction is \(r = k[2A]^2\) — Incorrect. The rate law contains the concentration of A, \( r = k[\mathrm{A}]^2 \); “[2A]” has no meaning as a concentration, and a coefficient in a balanced equation does not enter the brackets.
(D) The half-life of a second-order reaction depends on the initial concentration — Correct. \( t_{1/2} = 1/(k[\mathrm{A}]_0) \): the larger the initial concentration, the shorter the half-life. Only for a first order reaction is \( t_{1/2} \) independent of concentration.