A milkman has two type of milk. In the 1st container the percentage of milk is 80 and in the 2nd container the percentage of milk is 60. If he mixes 28 liters of the milk of 1st container to the 32 liter of milk of the 2nd container, then the percentage of milk in the mixture is:

\(69\frac{1 }{3}\)%

In the 1st container the percentage of milk = 80%

In the 2nd container the percentage of milk = 60%

If he mixes 28 liters of the milk of 1st container to the 32 liter of milk of the 2nd container =

Percentage of Milk in the mixture

=\(\frac{(80 × 28) + (60 × 32)}{28 + 32}\)

= \(\frac{[20×4]\;[(4 × 7) + (3 × 8)]}{4(7 + 8)}\)

= \(\frac{(20)(52)}{15}\)

= \(\frac{4\;(52)}{3}\)

= \(\frac{208}{3}\)

Percentage of Milk in the mixture = 69\(\frac{1}{3}\) %