Practicing Success
AB is a chord of a circle with centre O. C is a point on the circle in the minor sector. If ∠ ABO = 50°, then what is the degree measure of ∠ ACB ? |
100° 130° 110° 140° |
140° |
OA = OB = radius of the circle So, \(\angle\)ABO = \(\angle\)BAO = \({50}^\circ\) So, \(\angle\)AOB = \({180}^\circ\) - (\({50}^\circ\) - \({50}^\circ\)) ⇒ \(\angle\)AOB = \({180}^\circ\) - \({100}^\circ\) ⇒ \(\angle\)AOB = \({80}^\circ\) Let A and B meet at point D in the major sector Now, \(\angle\)ADB = \({80}^\circ\)/2 = \({40}^\circ\) ACBD is a cyclic quadrilateral So, \(\angle\)ACB = \({180}^\circ\) - \({40}^\circ\) ⇒ \(\angle\)ACB = \({140}^\circ\) Therefore, \(\angle\)ACB is \({140}^\circ\). |