Practicing Success
Evaluate the integral \(\int_0^5e^x\,dx=?\) |
1/3(e5 -1) -(e5 -1) (1+ e5) (e5 -1) |
(e5 -1) |
We have integral \(\int_0^5e^x\,dx=?\) ⇒ \(\int_0^5e^x\,dx=(e^x)\) for x = 0 to x= 5 = (e5 - e0) = (e5 -1)
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