The equation of a line passing through (1, -1, 0) and parallel to $\frac{x-2}{3}=\frac{2y+1}{2}=\frac{5-z}{-1}$, is

$\frac{x-1}{3}=\frac{y+1}{2}=\frac{z-0}{1}$

The equation of the given line can be re-written as $\frac{x-2}{3}=\frac{y+1/2}{1}=\frac{z-5}{1}$

Clearly, its direction ratios are proportional to 3, 1, 1. SO, direction ratios of parallel line are also proportional to 3, 1, 1.

Hence, the equation of the required line is $\frac{x-1}{3}=\frac{y+1}{1}=\frac{z-0}{1}$