Practicing Success
If $f(x)=\cos x \cos 2 x \cos 4 x \cos 8 x \cos 16 x$, then $f'\left(\frac{\pi}{4}\right)$ is |
$\sqrt{2}$ $\frac{1}{\sqrt{2}}$ 1 none of these |
$\sqrt{2}$ |
We have, $f(x)=\cos x \cos 2 x \cos 4 x \cos 8 x \cos 16 x$ $f\left(\frac{\pi}{4}\right)=0$ $\log f(x)=\log \cos x +\log \cos 2 x +\log \cos 4 x +\log \cos 8 x +\log \cos 16 x$ differentiating wrt x $\frac{df(x)}{dx}=-f(x)(\tan x+2\tan 2x+4\tan 4x+8\tan 8x+16\tan 16x)$ so $f'\left(\frac{\pi}{4}\right)=0$ as $f\left(\frac{\pi}{4}\right)=0$ |