Practicing Success
Practicing Success
CUET Preparation Today
A parallel plate air capacitor has a capacity 'C', distance of separation between its plates is 'x' and potential difference applied across the plates is V. What is the force of attraction between the plates of the parallel plate air capacitor ? |
$\frac{C^2 V^2}{2 x^2}$ $\frac{CV^2}{x}$ $\frac{C^2 V^2}{2 x}$ $\frac{CV^2}{2 x}$ |
$\frac{CV^2}{2 x}$ |
Electric Field due to one plate of capacitor due to other is $ E = \frac{V}{2x}$ Charge on plates of capacitor is $ q = CV$ Force of attraction is $ F = qE = \frac{CV^2}{2x}$ |
