The image of the point $(3,-2,1)$ in the plane $3 x-y+4 z=2$ is:

$(3,-1,4)$ $(0,-1,-3)$ $\left(\frac{3}{2},-\frac{5}{2},-1\right)$ $(0,1,3)$

$(0,-1,-3)$

The correct answer is Option (2) → $(0,-1,-3)$