Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

The speed v reached by a car of mass m in travelling a distance x, driven with constant power P, is given by : 

Options:

\(v = \frac{3xP}{m}\)

\(v = (\frac{3xP}{m})^{1/2}\)

\(v = (\frac{3xP}{m})^{1/3}\)

\(v = (\frac{3xP}{m})^2\)

Correct Answer:

\(v = (\frac{3xP}{m})^{1/3}\)

Explanation:

\(P = Fv = m\frac{dv}{dt} v\)

\(\Rightarrow v\frac{dv}{dt} = \frac{P}{m}\)

\(\Rightarrow v\frac{dv}{dx}{dx}{dt} = \frac{P}{m}\)

\(\Rightarrow v^2 \frac{dv}{dx} = \frac{P}{m}\)

\(\Rightarrow v^2 dv = \frac{P}{m} dx\)

\(\Rightarrow \int_0^v v^2 dv = \frac{P}{m} \int_0^x dx\)

\(\Rightarrow \frac{v^3}{3} = \frac{Px}{m}\)

\(\Rightarrow v = (\frac{3xP}{m})^{1/3}\)