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What is the area (in sq cm) of an equilateral triangle of side 11 cm? |
\(\frac{111}{4}\)\(\sqrt{3}\) \(\frac{121}{4}\)\(\sqrt{3}\) \(\frac{144}{4}\)\(\sqrt{3}\) \(\frac{196}{4}\)\(\sqrt{3}\) |
\(\frac{121}{4}\)\(\sqrt{3}\) |
Area of eq. = \(\frac{ \sqrt{3}}{4}\)a2 = \(\frac{ \sqrt{3}}{4}\) × 11 × 11 = \(\frac{121}{4}\)\(\sqrt{3}\) cm2 |
