The area (in sq. units) of the region {(x, y) : x \(\geq\) 0, x + y \(\leq\) 3, x2 \(\leq\) 4y and y \(\leq\) 1 + \(\sqrt{x}\)} is :
Answer & explanation
Correct answer: option 4
Area = \(\int_{0}^{1} (1 + \sqrt{x})dx + \frac{1}{2}(3 x 1) - \int_{0}^{2} \frac{x^2}{4} dx \)
= \(\frac{5}{2}\) sq. units.