In DNA N-glycosidic linkage is present between ____________.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A nitrogenous base and a Pentose sugar
Option (1) Pentose sugar and Phosphate group — Incorrect. The phosphate joins the 5' carbon of the sugar by a phosphoester linkage.
Option (2) A nitrogenous base and a Pentose sugar — Correct. The base joins the 1' carbon of the sugar, forming a nucleoside.
Option (3) Two nitrogenous bases — Incorrect. The bases of the two strands are held by hydrogen bonds.
Option (4) Two pentose sugars — Incorrect. Sugars of neighbouring nucleotides are linked through a phosphate by a 3'–5' phosphodiester linkage.
NCERT Extract:
Structure of Polynucleotide Chain – “… A nitrogenous base is linked to the OH of 1’ C pentose sugar through a N-glycosidic linkage to form a nucleoside, such as adenosine or deoxyadenosine, guanosine or deoxyguanosine, cytidine or deoxycytidine and uridine or deoxythymidine. When a phosphate group is linked to OH of 5' C of a nucleoside through phosphoester linkage, a corresponding nucleotide (or deoxynucleotide depending upon the type of sugar present) is formed.”