The radius of a circle is 15 cm and the length of one chord of the circle is 20 cm. What is the distance of the chord from the centre of the circle?

$5\sqrt{5}$ cm $5\sqrt{3}$ cm $5\sqrt{2}$ cm $3\sqrt{3}$ cm

$5\sqrt{5}$ cm

We know that, H2 = B2 + P2 We have, AB = 20 cm CA = \(\frac{1}{2}\) × AB = \(\frac{1}{2}\) × 20 = 10 cm OA = radius = 15 cm (OC)2 = (OA)2 – (CA)2 = (OC)2 = 152 – 102 = (OC)2 = 225 – 100 = OC = \(\sqrt {125}\) = 5\(\sqrt {5}\) cm