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The value of differentiation of $x^7 + 1 $ w.r.t $x^6$ is : |
$\frac{6x}{7}$ $\frac{7x}{6}$ $6x^2$ $\frac{6}{x}$ |
$\frac{7x}{6}$ |
$y=x^7+1.$ $u=x^6.$ $\frac{dy}{dx}=7x^6.$ $\frac{du}{dx}=6x^5.$ $\frac{dy}{du}=\frac{\frac{dy}{dx}}{\frac{du}{dx}}=\frac{7x^6}{6x^5}.$ $\frac{dy}{d(x^6)}=\frac{7}{6}x.$ $\frac{d(x^7+1)}{d(x^6)}=\frac{7x}{6}.$ |
