A particles of mass 1 × 10⁻²⁶kg and charge 1.6 × 10⁻¹⁹C travelling with a velocity 1.28 × 10⁶ ms⁻¹ along the positive X-axis enters a region in which a uniform electric field E and a uniform magnetic field of induction B are present. If $E = −10.24 × 10^3\hat{k}NC^{−1}\, and\, B = 8 × 10−2 \hat{j} Wbm^{−2}$, the direction of motion of the particles is

Along the positive X-axis

$m = 1 × 10^{-26} kg, q = 1.6 × 10^{-19} C,$

$ v = 1.28 × 10^6 ms^{-1}$

Electric field  $E = - 1024 × 10^3 \hat{k} NC^{-1}$

Magnetic field $ B = 8 × 10^{-2} \hat{j} Wbm^{-2}$

$ \frac{|E|}{|B|}=\frac{102.4×10^3}{8×10^{-2}}=\frac{10.24×10^6}{8}$

$= 1.28 × 10^6$

Hence, $ |v| = \frac{|E|}{|B|}$

So, particle will remain undeflected, hence direction of motion of particle is along the positive X-axis.