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CUET
-- Mathematics - Section B1
Continuity and Differentiability
If f(x) = |x - 2| and g(x) = f(f(x)), then for x > 20, g'(x) equals
-1
1
0
none of these
For x > 20, we have
∴ $f(x)=|x-2|=x-2$
and,
$g(x)=f(f(x))=f(x-2)=x-2-2=x-4$
$\Rightarrow g'(x)=1$