Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

If f(x) = |x - 2| and g(x) = f(f(x)), then for x > 20, g'(x) equals

Options:

-1

1

0

none of these

Correct Answer:

1

Explanation:

For x > 20, we have

∴  $f(x)=|x-2|=x-2$

and,

$g(x)=f(f(x))=f(x-2)=x-2-2=x-4$

$\Rightarrow g'(x)=1$