Practicing Success
The vector equation of the plane which is at a distance of 6 units from the origin and has2, -1, 2 as the direction ratios of normal to it, is : |
$\vec{r}. (2\hat{i}-\hat{j}+2\hat{k})= 18 $ $\vec{r}. (2\hat{i}-\hat{j}+2\hat{k})= 6$ $\vec{r}. (\hat{i}+\hat{j}+\hat{k})= 18 $ $\vec{r}. (\hat{i}+\hat{j}+\hat{k})= 6$ |
$\vec{r}. (2\hat{i}-\hat{j}+2\hat{k})= 18 $ |