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The focal length of a double convex lens is equal to the radius of curvature of either surface. The refractive index of its material is; |
0.5 1 1.5 2 |
1.5 |
1/f = (µ-1) (1/r1 + 1/r2) For this case r1 = r2 = f 1/r = (µ-1)(1/r+1/r) u-1= (1/r)/(1/r+1/r) =1/2 µ(refractive index) = 1+1/2 = 3/2 = 1.5 |
